# Projection on Polyhedral Cone

(Difference between revisions)
 Revision as of 15:28, 10 January 2010 (edit) (→Projection on isotone projection cones)← Previous diff Revision as of 20:13, 10 January 2010 (edit) (undo)Next diff → Line 35: Line 35: This cone is also an isotone projection cone. Projection onto this cone is equivalent to the This cone is also an isotone projection cone. Projection onto this cone is equivalent to the - [http://en.wikipedia.org/wiki/Isotonic_regression isotonic regression problem] with nonnegative variables given by the weight vector $w=(w_1,\dots,w_n)^\top$ and a [http://en.wikipedia.org/wiki/Totally_ordered_set total order]. + isotonic regression problem with nonnegative variables given by the weight vector $w=(w_1,\dots,w_n)^\top$ and a total order. The isotone projection cones were introduced by George Isac and A. B. Németh in the mid-1980's and then applied by George Isac, A. B. Németh, and S. Z. Németh to [[Complementarity_problem | complementarity problems]] (see [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:0719.46011&format=complete 1], [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:0711.47030&format=complete 2], [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:1152.90623&format=complete 3] and [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:1162.47050&format=complete 4]). The algorithm below opens the way for efficient implementations of the iterative methods in [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:0719.46011&format=complete 1], [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:0711.47030&format=complete 2] and [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:1162.47050&format=complete 4]. For simplicity we shall call a matrix $\mathbf E ,$ whose columns are generators of an isotone projection cone, an '''isotone projection cone generator matrix'''. Recall that an L-matrix is a matrix whose diagonal entries are positive and off-diagonal entries are nonpositive. A matrix $\mathbf E$ is an isotone projection cone generator matrix if and only if it is of the form The isotone projection cones were introduced by George Isac and A. B. Németh in the mid-1980's and then applied by George Isac, A. B. Németh, and S. Z. Németh to [[Complementarity_problem | complementarity problems]] (see [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:0719.46011&format=complete 1], [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:0711.47030&format=complete 2], [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:1152.90623&format=complete 3] and [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:1162.47050&format=complete 4]). The algorithm below opens the way for efficient implementations of the iterative methods in [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:0719.46011&format=complete 1], [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:0711.47030&format=complete 2] and [http://www.zentralblatt-math.org/zmath/en/advanced/?q=an:1162.47050&format=complete 4]. For simplicity we shall call a matrix $\mathbf E ,$ whose columns are generators of an isotone projection cone, an '''isotone projection cone generator matrix'''. Recall that an L-matrix is a matrix whose diagonal entries are positive and off-diagonal entries are nonpositive. A matrix $\mathbf E$ is an isotone projection cone generator matrix if and only if it is of the form

## Revision as of 20:13, 10 January 2010

This is an open problem in Convex Optimization. At first glance, it seems rather simple; the problem is certainly easily understood:

We simply want a formula for projecting a given point in Euclidean space on a cone described by the intersection of an arbitrary number of halfspaces;
we want the closest point in the polyhedral cone.

By "formula" I mean a closed form; an equation or set of equations (not a program, algorithm, or optimization).
A set of formulae, the choice of which is conditional, is OK as long as size of the set is not factorial (prohibitively large).

This problem has many practical and theoretical applications. Its solution is certainly worth a Ph.D. thesis in any Math or Engineering Department.

## Projection on isotone projection cones

Together with my coauthor A. B. Németh we recently discovered a very simple algorithm in $LaTeX: \mathbb R^n$ for projecting onto a special class of cones: the isotone projection cones.

An isotone projection cone is a generating pointed closed convex cone $LaTeX: \mathcal{K}$ in a Hilbert space $LaTeX: \mathbb{H}$ for which projection $LaTeX: P_\mathcal{K}$ onto the cone is isotone; that is, monotone with respect to the order $LaTeX: \preceq$ induced by the cone: $LaTeX: \forall\,x\,,\,y\in\mathbb{H}$

$LaTeX: x\preceq y\Rightarrow P_\mathcal{K}(x)\preceq P_\mathcal{K}(y),$

or equivalently

$LaTeX: y-x\in\mathcal K\Rightarrow P_\mathcal{K}(y)-P_\mathcal{K}(x)\in\mathcal K.$

From now on, suppose that we are in $LaTeX: \mathbb R^n$. Here the isotone projection cones are polyhedral cones generated by $LaTeX: n$ linearly independent vectors (i.e., cones that define a lattice structure; called latticial or simplicial cones) such that the generators of the polar cone form pairwise nonacute angles. For example, the nonnegative monotone cone (Example 2.13.9.4.2 in CO&EDG) is an isotone projection cone. The nonnegative monotone cone is defined by

$LaTeX: \left\{(x_1,\dots,x_n)^\top\in\mathbb R^n \mid x_1\geq\dots\geq x_n\geq 0\right\}.$

Projecting onto nonnegative monotone cones (see Section 5.13.2.4 in CO&EDG) is important for the problem of map-making from relative distance information (see Section 5.13 in CO&EDG); e.g., stellar cartography. If $LaTeX: w_1,\dots,w_n>0$ an extension of the nonnegative monotone cone is defined by

$LaTeX: \left\{(x_1,\dots,x_n)^\top\in\mathbb R^n \mid \frac{x_1}{\sqrt{w_1}}\geq\dots\geq \frac{x_n}{\sqrt{w_n}}\geq 0\right\}.$

This cone is also an isotone projection cone. Projection onto this cone is equivalent to the isotonic regression problem with nonnegative variables given by the weight vector $LaTeX: w=(w_1,\dots,w_n)^\top$ and a total order. The isotone projection cones were introduced by George Isac and A. B. Németh in the mid-1980's and then applied by George Isac, A. B. Németh, and S. Z. Németh to complementarity problems (see 1, 2, 3 and 4). The algorithm below opens the way for efficient implementations of the iterative methods in 1, 2 and 4. For simplicity we shall call a matrix $LaTeX: \mathbf E ,$ whose columns are generators of an isotone projection cone, an isotone projection cone generator matrix. Recall that an L-matrix is a matrix whose diagonal entries are positive and off-diagonal entries are nonpositive. A matrix $LaTeX: \mathbf E$ is an isotone projection cone generator matrix if and only if it is of the form

$LaTeX: \mathbf E=\mathbf O\mathbf T^{-\frac12},$

where $LaTeX: \mathbf O$ is an orthogonal matrix and $LaTeX: \mathbf T$ is a positive definite L-matrix.

The algorithm is a finite one that stops in at most $LaTeX: \,n$ steps and finds the exact projection point. Suppose that we want to project onto a latticial cone, and for each point in Euclidean space we know a proper face of the cone onto which that point projects. Then we could find the projection, recursively, by projecting onto linear subspaces of decreasing dimension. In case of isotone projection cones, the isotonicity property provides information required about such a proper face. The information is provided by geometrical structure of the polar cone. The theoretical background for the algorithm is Moreau's decomposition theorem.

If a polyhedral cone can be written as a union of isotone projection cones, reasonably small in number, then we could project a point onto the polyhedral cone by projecting onto the isotone projection cones and then taking the minimum distance of the given point from all these cones. Due to simplicity of the method for projecting onto an isotone projection cone, it is a challenging open question to find polyhedral cones that comprise a union of a small number of isotone projection cones that can be easily discerned. We conjecture that the latticial cones, which are subsets of the nonnegative orthant (or subsets of an isometric image of the nonnegative orthant), are such cones.

Our method of projection onto an isotone projection cone is contained in a paper accepted for publication at Linear Algebra and its Applications.

Matlab code for the algorithm:

% You are free to use, redistribute, and modifiy this code if you include,
% as a comment, the author of the original code
% (c) Sandor Zoltan Nemeth, 2009.
function p=piso(x,E)
[n,n]=size(E);
if det(E)==0, error('The input cone must be an isotone projection cone'); end
V=inv(E);
U=-V';
F=-V*U;
G=F-diag(diag(F));
for i=1:n
for j=1:n
if G(i,j)>0
error('The input cone must be an isotone projection cone');
end
end
end
I=[1:n];
n1=n-1;
cont=1;
for k=0:n1
[q1,l]=size(I);
E1=E;
I1=I;
if l-1>=1
highest=I(l);
if highest<n
for h=n:-1:highest+1
E1(:,h)=zeros(n,1);
end
end
for j=l-1:-1:1
low=I(j)+1;
high=I(j+1)-1;
if high>=low
for m=high:-1:low
E1(:,m)=zeros(n,1);
end
end
lowest=I(1);
if lowest>1
for w=lowest-1:-1:1
E1(:,w)=zeros(n,1);
end
end
end
end
if l==1
E1=zeros(n,n);
E1(:,I(1))=E(:,I(1));
end

V1=pinv(E1);
U1=-V1';

for j=l:-1:1
zz=x'*U1(:,I(j));
if zz>0, I1(j)=[];
end
end
[q2,ll]=size(I1);
if cont==0, p=x; return
elseif ll==0, p=zeros(n,1); return
else
A=E1*V1;
x=A*x;
p=x;
end
if ll==l, cont=0;
else cont=1;
end
I=I1;
end


## Fast projection on monotone nonnegative cone

Demo requires CVX to produce estimate of error by solving the projection problem in polynomial time.

CVX is not required for piso4() which performs projection by Sándor's method about 100 times faster.

%demo: Sandor's projection on monotone nonnegative cone
%-Jon Dattorro, August 2, 2009
clear all
n = 100;
cvx_quiet('true')
cvx_precision('high')
a = randn(n,1);
tic
t = piso4(a);
fprintf('\n')
toc
if n < 500
tic
cvx_begin
variable s(n,1);
variable b(n,1);
minimize(norm(s-a));
for i=1:n
s(i) == sum(b(i:n));
end
b >= 0;
cvx_end
toc
err = sum(abs(s - t))
end


### piso4()

This code is optimized for memory efficiency. Otherwise, for $LaTeX: n=$millions of variables, required memory would be measured in terabytes.

% -Sandor Zoltan Nemeth, with code optimization -Jon Dattorro August 2, 2009.
% Project x on monotone nonnegative cone of dimension n.
function p = piso4(x)
n = length(x);
I = 1:n;
disp('_____')
for k=1:n
fprintf('\b\b\b\b\b\b%6d',k);
L = length(I);
zeroidx = 1:n;
zeroidx(I) = [];
V1 = getpinv2(zeroidx,n);
I(find(V1(I,:)*x<0)) = [];
newL = length(I);
if ~newL
p = sparse(n,1);
return
else
t = V1*x;
s = sum(t);
zs = sum(t(zeroidx));
for i=1:n
x(i) = s - zs;
s = s - t(i);
first = find(zeroidx>=i,1);
zs = zs - sum(t(zeroidx(1:first-1)));
zeroidx(1:first-1) = [];
end
end
if newL==L
p = x;
return
end
end


### getpinv2()

%Assumes Platonic upper triangular ones (generator matrix) with some columns missing.
%Quickly finds pseudoinverse of monotone nonnegative cone generator matrix
%June 14, 2009  -Jon Dattorro

function Y = getpinv2(zeroidx,n);
Y = spdiags([ones(n,1), -ones(n,1)], [0 1], sparse(n,n));
Y(zeroidx,:) = 0;
%find dangling -1
count = 0;
for i=1:n
if ~Y(i,i)
count = count + 1;
if i-1 > 0
Y(i-1,i) = 0;
end
else
if count
if i-count-1 > 0
Y(i-count-1,i-count:i) = -1/(count+1);
end
Y(i,i-count:i) = 1/(count+1);
end
count = 0;
end
end


## Projection on simplicial cones

The following method was developed together with my coauthors A. Ekárt and A. B. Németh. Thanks are due to J. Dattoro for his continuous support and encouragement.

Suppose that $LaTeX: \mathcal K$ is a simplicial cone generated by the linearly independent vectors $LaTeX: \,e^i$ in $LaTeX: \mathbb R^n$ and $LaTeX: \mathcal K^\circ$ is its polar generated by the linearly independent vectors $LaTeX: \,u^j.$ Then $LaTeX: (e^i)^\top u^j = -\delta_{ij},$ where $LaTeX: \,\delta_{ij}$ is the Kronecker symbol.

Theorem

Let $LaTeX: x\in\mathbb R^n.$ For each subset of indices $LaTeX: I\subset\{1,\dots,n\},$ $LaTeX: \,x$ can be represented in the form

$LaTeX: x=\sum_{i\in I}\alpha_i e^i+\sum_{j\in I^c}\beta_j u^j\quad [1]$

with $LaTeX: \,I^c$ the complement of $LaTeX: I$ with respect to $LaTeX: \,\{1,\dots,n\},$ and with $LaTeX: \,\alpha_i$ and $LaTeX: \,\beta_j$ real numbers. Among the subsets $LaTeX: \,I$ of indices, there exists exactly one (the cases $LaTeX: I=\emptyset$ and $LaTeX: \,I=\{1,\dots,n\}$ are not excluded) with the property that for the coefficients in $LaTeX: \,[1]$ one has $LaTeX: \,\beta_j>0,$ $LaTeX: j\in I^c$ and $LaTeX: \,\alpha_i\geq 0,$ $LaTeX: \,i\in I.$ For this representation it holds that

$LaTeX: P_{\mathcal K}(x)=\sum_{i\in I} \alpha_i e^i,\quad \alpha_i\geq 0$

and

$LaTeX: P_{\mathcal K^\circ}(x)=\sum_{j\in I^c}\beta_j u^j,\quad \beta^j>0.$

This theorem suggests the following algorithm for finding the projection $LaTeX: P_{\mathcal K}(x):$

Step 1. For the subset $LaTeX: I\subset\{1,\dots,n\}$ we solve the following linear system in $LaTeX: \alpha^i$

$LaTeX: x^\top e^\ell =\sum_{i\in I}\alpha_i (e^\top)^i e^\ell,\;\ell\in I.\quad [2]$

Step 2. Then, we select from the family of all subsets in $LaTeX: \{1,\dots,n\}$ the subfamily $LaTeX: \,\Delta$ of subsets $LaTeX: \,I$ for which the system possesses non-negative solutions.

Step 3. For each $LaTeX: I\in \Delta$ we solve the linear system in $LaTeX: \,\beta^j$

$LaTeX: x^\top u^k = \sum_{j\in I^c}\beta_j (u^j)^\top u^k,\;k\in I^c.\quad [3]$

By the above Theorem among these systems there exists exactly one with non-negative solutions. By the same theorem, for corresponding $LaTeX: \,I$ and for the solution of the system $LaTeX: \,[2],$ we must have

$LaTeX: P_{\mathcal K}(x)=\sum_{i\in I}\alpha_i e^i.$

This algorithm requires that we solve $LaTeX: \,2^n$ linear systems of at most $LaTeX: \,n$ equations in Step 1 $LaTeX: \,[2]$ and another $LaTeX: \,2^{|\Delta|}$ systems in Step 2 $LaTeX: \,[3].$ (Observe that all these systems are given by Gram matrices, hence they have unique solutions.) The above presented method is inefficient but it suggests the following heuristic algorithm:

Substitute $LaTeX: \,u^j$ with $LaTeX: \,e^j$ if $LaTeX: \,\beta_j<0$ and substitute $LaTeX: \,e^i$ with $LaTeX: \,u^i$ if $LaTeX: \,\alpha_i<0$ and solve the systems $LaTeX: \,[2]$ and $LaTeX: \,[3]$ for the new configuration of indices $LaTeX: \,I.$ We shall call this step an iteration of the heuristic algorithm.

Then, repeat the procedure for the new configuration of $LaTeX: \,I$ and so on, until we obtain a representation of $LaTeX: \,x$ in $LaTeX: \,[1]$ with all the coefficients non-negative.

The extensive experiments indicate that the method furnishes the exact solution in more then $LaTeX: \,99.7$ percent of the cases. The average number of steps is $LaTeX: \,5.67$ (we have not found any examples which required more than $LaTeX: \,13$ steps) and the relative number of steps with respect to the dimension decreases dramatically. Roughly speaking, for high enough dimensions the absolute number of steps is independent of the dimension. The percentage of problems where the algorithm was aborted due to going in a loop exponentially decreases as the size increases. The percentage of loops above sizes of $LaTeX: \,30$ is less than $LaTeX: \,0.001\%.$ Overall, loops were observed in less than $LaTeX: \,0.3\%$ of the experiments, so the heuristic algorithm was successful more than $LaTeX: 99.7\%$ of the time. Most of the loops were observed for problems of very small size ($LaTeX: \,2,$ $LaTeX: \,3$ and $LaTeX: \,5$). The conclusions are based on millions of numerical experiments.